Quick Fix: %lu
is the format specifier for unsigned long
in C’s printf
. Make sure to include the correct header <inttypes.h>
for this to work.
The Solutions:
Solution 1: Use the correct format specifier
The correct format specifier for printing an unsigned long is `%lu`.
Solution 2: Use the correct format specifier for unsigned long
The correct format specifier for printing an unsigned long
is %lu
. The other format specifiers you tried are for different data types:
%d
is for signed integers%ld
is for signed long integers%ll
is for signed long long integers%dl
is not a valid format specifier
Here’s an example of how to print an unsigned long
:
unsigned long unsigned_foo = 1234567890;
printf("%lu\n", unsigned_foo); // prints 1234567890
Solution 3:
To print an unsigned long in C, use the format specifier `%lu`. For example:
#include <stdio.h>
int main() {
unsigned long unsigned_foo = 1234567890;
printf("%lu\n", unsigned_foo); // prints 1234567890
}
Solution 4: Remove %d family format specifiers
Out of all the combinations you tried, %ld
and %lu
are the only ones which are valid printf format specifiers at all. %lu
(long unsigned decimal), %lx
or %lX
(long hex with lowercase or uppercase letters), and %lo
(long octal) are the only valid format specifiers for a variable of type unsigned long (of course you can add field width, precision, etc modifiers between the %
and the l
).